Cody is
p years old. Paul is four times as old as Cody and Dylan is 4 years younger than Paul.
- Express Dylan's age in terms of p.
- Cody is 8 years old as of now. ln how many years' time will Dylan be 3 times as old as Cody?
(a)
Cody's age =
p years
Paul's age = 4
p years
Dylan's age = (4
p - 4) years
(b)
p = 8
Difference in age remains unchanged.
Difference in age between Dylan and Cody
= (4
p - 4) -
p = 4
p -
p - 4
= 3
p - 4
= 3 x 8 - 4
= 20 years
Difference in the age when Dylan will be 3 times as old as Cody
= 3 u - 1 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of years' time so Dylan will be 3 times as old as Cody
= 10 - 8
= 2 years
Answer(s): (a) (4
p - 4) years; (b) 2 years
