Howard is
r years old. Lee is six times as old as Howard and Albert is 14 years younger than Lee.
- Express Albert's age in terms of r.
- Howard is 8 years old as of now. ln how many years' time will Albert be 3 times as old as Howard?
(a)
Howard's age =
r years
Lee's age = 6
r years
Albert's age = (6
r - 14) years
(b)
r = 8
Difference in age remains unchanged.
Difference in age between Albert and Howard
= (6
r - 14) -
r = 6
r -
r - 14
= 5
r - 14
= 5 x 8 - 14
= 26 years
Difference in the age when Albert will be 3 times as old as Howard
= 3 u - 1 u
= 2 u
2 u = 26
1 u = 26 ÷ 2 = 13
Number of years' time so Albert will be 3 times as old as Howard
= 13 - 8
= 5 years
Answer(s): (a) (6
r - 14) years; (b) 5 years
