There were 6 more 5-cent coins than 20-cent coins in a handbag. Given that the value of all the 20-cent coins were $7.35 more than the value of all the 5-cent coins, how many 5-cent coins were there in the handbag?
| |
20-cent |
5-cent |
Difference |
| Number |
1 u |
1 u + 6 |
|
| Value |
0.20 |
0.05 |
|
| Total value |
0.2 u |
0.05 u + 0.3 |
0.15 u - 0.3 |
Total value of 20-cent coins
= 1 u x 0.20
= 0.2 u
Total value of 5-cent coins
= 0.05 x (1 u + 6)
= 0.05 u + 0.30
Total value of the 20-cent coins that is more than the total value of the 5-cent coins
= 0.2 u - (0.05 u + 0.3)
= 0.2 u - 0.05 u - 0.3
= 0.15 u - 0.3
0.15 u - 0.3 = 7.35
0.15 u = 7.35 + 0.3
0.15 u = 7.65
1 u = 7.65 ÷ 0.15 = 51
Number of 5-cent coins
= 1 u + 6
= 51 + 6
= 57
Answer(s): 57
