A bag consists of a number of 20-cent and 50-cent coins. There are 85% as many 20-cent coins as 50-cent coins. How much money is there in the bag if there are 45 more 50-cent coins than 20-cent coins?
85% =
85100 =
1720
| 20-cent |
50-cent |
Difference |
| 17 u |
20 u |
3 u |
Number of 20-cent coins = 17 u
Number of 50-cent coins = 20 u
Difference in the number of coins = 20 u - 17 u = 3 u
3 u = 45
1 u = 45 ÷ 3 = 15
Number of 50-cent coins
= 20 u
= 20 x 15
= 300
Number of 20-cent coins
= 17 u
= 17 x 15
= 255
Amount of money in the bag
= 255 x 0.20 + 300 x 0.50
= 51 + 150
= $201
Answer(s): $201
