Bryan, Liam and Gabriel shared a sum of money. The amount received by Liam was
56 the amount of money received by Gabriel. After Bryan had given $53 to Liam and $20 to Gabriel, Liam gave $7 to Gabriel. In the end, 3 of them had the same amount of money. Find the difference between the amount of money that Bryan and Liam had at first.
|
Bryan |
Liam |
Gabriel |
Before |
5 u + 119 |
5 u |
6 u |
Change 1 |
- 53 |
+ 53 |
|
Change 2 |
- 20 |
|
+ 20 |
Change 3 |
|
- 7 |
+ 7 |
After |
5 u + 46 |
5 u + 46 |
6 u + 27 |
Amount that Liam had in the end = 5 u + 46
Amount that Gabriel had in the end = 6 u + 27
Amount that Bryan had at first
= 5 u + 46 + 53 + 20
= 5 u + 119
Amount that Liam and Gabriel had in the end is the same.
5 u + 46 = 6 u + 27
6 u - 5 u = 46 - 27
1 u = 19
Amount that Bryan and Liam had in the end is the same.
Amount that Bryan had in the end
= 5 u + 46
= 5 x 19 + 46
= 95 + 46
= $141
Amount that Bryan had at first
= 141 + 53 + 20
= $214
Difference in the amounts between Bryan and Liam at first
= 214 - 95
= $119
Answer(s): $119