Dylan had a total of 162 blue and black balls. After giving away
12 of the blue balls and 69 black balls, there was an equal number of blue and black balls left. How many blue balls did he have at first?
| |
Blue balls |
Black balls |
Total |
| Before |
2 u |
1 u + 69 |
162 |
| Change |
- 1 u |
- 69 |
|
| After |
1 u |
1 u |
|
Total number of balls at first
= 2 u + 1 u + 69
= 3 u + 69
3 u + 69 = 162
3 u = 162 - 69
3 u = 93
1 u = 93 ÷ 3 = 31
Number of blue balls that Dylan had at first
= 2 u
= 2 x 31
= 62
Answer(s): 62
