The figure, not drawn to scale, is made up of 3 different triangles H, J and K. 25% of triangle H and 30% of triangle K is shaded. The shaded area of H is the same as the shaded area of K. What fraction of the figure is shaded if 20% of Triangle J is shaded?

Unshaded area of H	Shaded area of H	Unshaded area of K	Shaded area of K
3x3	1x3	7x1	3x1
9 u	3 u	7 u	3 u

25% = ²⁵₁₀₀ = ¹₄
30% = ³⁰₁₀₀ = ³₁₀
20% = ²⁰₁₀₀ = ¹₅
The shaded area of H is the same as the shaded area of K.

Make the LCM of the shaded area of H and shaded area of K the same.
LCM of 1 and 3 = 3

¹₅ of J is shaded
= Shaded area of H + Shaded area of K
= 3 u + 3 u
= 6 u

Fraction of J that is unshaded 
= 1 - ¹₅
= ⁴₅ 

¹₅ of J = 6 u
⁴₅ of J = 4 x 6 u = 24 u

Fraction of the figure that is shaded if 20% of Triangle J is shaded
= ^{6 + 6}_{9 + 24 + 7 + 6 + 6}
= ¹²₅₂
= ³₁₃

Answer(s): ³₁₃