City R and City S are 316 km apart. At 4.19 p.m., Andy is travelling at a uniform speed left City R for City S while Howard set off from City S to City R along the same road at a uniform speed, which was 6 km/h slower than that of Andy. The two met at 6.19 p.m.

1. Find the speed of Andy.
2. If Howard continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Andy and Howard to travel from 4.19 p.m. to 6.19 p.m. = 2 h

Average speed of Andy and Howard
= 316 ÷ 2
= 158 km/h

Andy's speed
= (158 + 6) ÷ 2
= 164 ÷ 2 
= 82 km/h

(b)
Howard's speed
= 82 - 6
= 76 km/h

Distance that Howard travelled in 2 h
= 2 x 76
= 152 km

Remaining distance that Howard needed to travel
= 316 - 152
= 164 km

Time that Howard needed to reach his destination after the two met
= 164 ÷ 76
= 2¹²₇₆
= 2³₁₉ h

Answer(s): (a) 82 km/h; (b) 2³₁₉ h