At 06 20, Yen left Town N and cycled towards Town P. Elyse left Town N and cycled towards Town P at 06 40. Elyse's cycling speed was 3 km/h faster than Yen. At 10 20, Elyse caught up with Yen. Find the cycling speed of each cyclist.
- Yen
- Elyse
(a)
Duration that Elyse cycled from 06 40 to 10 20
= 3
4060 = 3
23 h
Distance that Elyse cycled more than Yen
= 3
23 x 3
= 11 km
However, since Yen left 20 minutes earlier than Elyse and Elyse caught up with Yen, it means that Yen has cycled 11 km in 20 min.
1 h = 60 min
20 min = 20 ÷ 60 =
13 h
Yen's cycling speed
= 11 ÷
13 = 11 x
31 = 33 km/h
(b)
Elyse's cycling speed
= 33 + 3
= 36 km/h
Answer(s): (a) 33 km/h ; (b) 36 km/h
