Daniel left City T for City S at 07 46. Winnie left City T for City C at the same time. At 10 46, they were 480 km apart. Both maintained a constant speed and reached their destination at the same time at 12 22.

1. Find the distance between Cities A and C.
2. If Winnie was ³₅ the speed of Daniel, find Daniel's speed.

(a)
Time taken for Daniel and Winnie to travel 07 46 to 10 46 = 3 h
Time taken for Daniel and Winnie to travel 07 46 to 12 22 = 4 h 36 min = 4³⁶₆₀ h = 4³₅ h

Distance travelled by Daniel and Winnie in 1 hour
= 480 ÷ 3
= 160 km

Total distance
= 4³₅ x 160
= 736 km

(b)
Winnie's distance : Daniel's distance
3 : 5

Winnie's speed : Daniel's speed
3 : 5

8 u = 160 km
1 u = 160 ÷ 8 = 20 km

Daniel's speed
= 5 u
= 5 x 20
= 100 km/h

Answer(s): (a) 736 km; (b) 100km/h