Mary had some chikoos and mangoes in 2 baskets. In Basket P, the number of chikoos to the number of mangoes was in the ratio of 3 : 8. In Basket Q, there were thrice as many chikoos as mangoes. After Mary transferred
34 of the mangoes from Basket P to Basket Q, the number of fruits left in Basket P was 150 and the ratio of the number of chikoos to the number of mangoes in Basket B became 6 : 7. How many fruits were in Basket Q in the end?
|
Basket P |
Basket Q |
|
Chikoos |
Mangoes |
Chikoos |
Mangoes |
Before |
3 u |
8 u |
3x2 = 6 p |
1x2 = 2 p |
Change |
|
- 6 u |
|
+ 6 u (+ 5 p) |
After |
3 u |
2 u |
6x1 = 6 p |
7x1 = 7 p |
Number of mangoes that Mary transferred from Basket P to Basket Q
=
34 x 8 u
= 6 u
Total number of fruits in Basket P in the end
= 3 u + 2 u
= 5 u
5 u = 150
1 u = 150 ÷ 5 = 30
The number of chikoos in Basket Q is the unchanged quantity.
LCM of 3 and 6 is 6.
Number of mangoes that Mary transferred from Basket P to Basket Q
= 6 u
= 6 x 30
= 180
Increase in the number of mangoes that due to the transfer from Basket P to Basket Q
= 7 p - 2 p
= 5 p
5 p = 6 u
5 p = 180
1 p = 180 ÷ 5 = 36
Number of fruits in Basket Q in the end
= 6 p + 7 p
= 13 p
= 13 x 36
= 468
Answer(s): 468