Min and Jade collected beads. Jade gave 80% of her beads to Min. As a result, Min's beads increased by 25%. If Min had 200 beads left, find the total number of beads the two girls had at first.
| |
Comparing the change
in Jade's beads |
Jade |
Min |
| Before |
5x1 =
5 u |
|
4x4 =
16 u |
| Change |
- 4x1 =
- 4 u |
- 1x4 =
- 4 u |
+ 1x4 =
+ 4 u |
| After |
1x1 =
1 u |
|
5x4 =
20 u |
80% =
80100 =
45 25% =
25100 =
14 The number of beads that Min gave to Jade is repeated. Make the number of beads that Min gave to Jade the same. LCM of 1 and 4 is 4.
Number of beads that Min had in the end = 20 u
20 u = 200
1 u = 200 ÷ 20 = 10
Number of beads that Jade and Min had at first
= 5 u + 16 u
= 21 u
= 21 x 10
= 210
Answer(s): 210
