At a safari park, there were
47 as many adults as children at first. After 60 adults left, there were 102 more children than adults remaining at a safari park. How many children were at the safari park?
|
Adults |
Children |
Before |
4 u |
7 u |
Change |
- 60 |
|
After |
4 u - 60 |
7 u |
In the end, the number of children was 102 more than the number of adults. If another 102 adults entered the safari park, the number of children and adults would be the same.
7 u = 4 u - 60 + 102
7 u - 4 u = 102 - 60
3 u = 42
1 u = 42 ÷ 3 = 14
Number of children at first
= 7 u
= 7 x 14
= 98
Answer: 98