Liam has $10. Eric has $5
x more than Liam. Brandon has $2
x less than Eric.
- Find the amount of money that Brandon has in terms of x.
- Find the total amount of money that the three boys have in terms of x.
- If x = 6, how much does Brandon have?
(a)
Amount that Liam has = $10
Amount that Eric has = $(10 + 5
x)
Amount that Brandon has
= 10 + 5
x - 2
x = $(10 + 3
x)
(b)
Total amount that the three boys have
= 10 + 10 + 5
x + 10 + 3
x= 10 + 10 + 10 + 5
x + 3
x = $(30 + 8
x)
(c)
Amount that Brandon has
= 10 + 3
x= 10 + 3 x 6
= 10 + 18
= $28
Answer(s): (a) $(10 + 3
x) or $(3
x + 10); (b) $(30 + 8
x) or $(8
x + 30); (c) $28