Jenson is
f years old. Lee is six times as old as Jenson and Daniel is 6 years younger than Lee.
- Express Daniel's age in terms of f.
- Jenson is 9 years old as of now. ln how many years' time will Daniel be 4 times as old as Jenson?
(a)
Jenson's age =
f years
Lee's age = 6
f years
Daniel's age = (6
f - 6) years
(b)
f = 9
Difference in age remains unchanged.
Difference in age between Daniel and Jenson
= (6
f - 6) -
f = 6
f -
f - 6
= 5
f - 6
= 5 x 9 - 6
= 39 years
Difference in the age when Daniel will be 4 times as old as Jenson
= 4 u - 1 u
= 3 u
3 u = 39
1 u = 39 ÷ 3 = 13
Number of years' time so Daniel will be 4 times as old as Jenson
= 13 - 9
= 4 years
Answer(s): (a) (6
f - 6) years; (b) 4 years
