The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube M and Cube N. The tank is filled with some water. Cube M is ⁴₅ filled with 100000 mℓ of water while Cube N is completely filled with water. The height of the water level in Cube M is 10 cm higher than that in Cube N. Water is then drained from the tank and the height of the new water level is 7 cm. What is the volume of the water drained in mℓ?
⁴₅ of the volume of Cube M = 100000 mℓ

Volume of Cube M
= 100000 ÷ ⁴₅
= 100000 x ⁵₄
= 125000 mℓ

Length of Cube M
= ³√125000
= 50 cm 

Height of water in Cube M at first
= ⁴₅ x 50
= 40 cm

Height of Cube N
= 40 - 10
= 30 cm

Height decrease in water in Cube M after draining
= 40 - 7
= 33 cm

Height decrease in water in Cube M after draining
= 30 - 7
= 23 cm

Volume of water drained in Cube M
= 50 x 50 x 33
= 82500 mℓ

Volume of water drained in Cube N
= 30 x 30 x 23
= 20700 mℓ

Total volume of water drained
= 82500 + 20700
= 103200 mℓ

Answer(s): 103200 mℓ