At first, Containers B, C and D contained water as shown. Some water from Containers C and D was poured into Container B without any spilling over. The volume of water left in Containers C and D is shown. What would be the volume of water in Container B?
1 ℓ = 1000 mℓ

Volume of water at each division on Container B
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container B at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container C
= 800 ÷ 10
= 80 mℓ

Volume of water in Container C
= 8 x 80
= 640 mℓ

Volume of water at each division in Container D
= 600 ÷ 10
= 60 mℓ

Amount of water contained in Container D
= 9 x 60
= 540 mℓ

Total volume of water in Container C and Container D
= 640 + 540
= 1180 mℓ

Volume of water in Container C after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container D after pouring
= 6 x 60
= 360 mℓ

Volume of water in Container C and Container D
= 480 + 360
= 840 mℓ

Volume of water poured in Container B
= 1180 - 840
= 340 mℓ

Total volume of water in Container B
= 600 + 340
= 940 mℓ

Answer(s): 940 mℓ