At first, Containers M, N and P contained water as shown. Some water from Containers N and P was poured into Container M without any spilling over. The volume of water left in Containers N and P is shown. What would be the volume of water in Container M?
1 ℓ = 1000 mℓ

Volume of water at each division on Container M
= 1000 ÷ 10
= 100 mℓ

Volume of water in Container M at first
= 6 x 100
= 600 mℓ

Volume of water at each division on Container N
= 800 ÷ 10
= 80 mℓ

Volume of water in Container N
= 8 x 80
= 640 mℓ

Volume of water at each division in Container P
= 500 ÷ 10
= 50 mℓ

Amount of water contained in Container P
= 9 x 50
= 450 mℓ

Total volume of water in Container N and Container P
= 640 + 450
= 1090 mℓ

Volume of water in Container N after pouring
= 6 x 80
= 480 mℓ

Volume of water in Container P after pouring
= 6 x 50
= 300 mℓ

Volume of water in Container N and Container P
= 480 + 300
= 780 mℓ

Volume of water poured in Container M
= 1090 - 780
= 310 mℓ

Total volume of water in Container M
= 600 + 310
= 910 mℓ

Answer(s): 910 mℓ