N and P are two rectangular tanks. The base area of N is 77 cm
2 while that of P is 46 cm
2 . At first, N contained water to a height of 56 cm and P was empty, as shown.
- What was the volume of the water in N at first?
- Luis then poured some water from N to P. After that, the height of the water level in N was twice that in P. What was the new height of the water level in N?
(a)
Volume of water in N
= 77 x 56
= 4312 cm
3 (b)
Total base areas
= 77 + 77 + 46
= 200 cm
2 Height of water if the total base area is 200 cm
2 = 4312 ÷ 200
= 21.56 cm
New height of the water level in N
= 21.56 x 2
= 43.12 cm
Answer(s): (a) 4312 cm
3; (b) 43.12 cm