The figure, not drawn to scale, is made of two connected cubical containers, Z and A. Container Z is sealed at the top and completely filled to the brim. Container A is ⁴₅ filled with 101820 mℓ of water. The height of the water level in Container A is 4 cm higher than that in Container Z. Height of Container A is 65 cm. Water is then drained from the container and the height of the water level from the base falls to 37 cm.

1. What is the capacity of Container A in litres?
2. What is the volume of water in the container now in litres?

(a)
⁴₅ of Container A = 101820 mℓ
¹₅ of Container A = 101820 ÷ 4 = 25455 mℓ
⁵₅ of Container A = 25455 x 5 = 127275 mℓ

1 ℓ = 1000 mℓ

Capacity of Container A = 127275 mℓ = 127.275 ℓ

(b)
Fraction of Container A not filled
= 1 - ⁴₅
= ¹₅

Height of Container A not filled
= ¹₅ x 65 cm
= 13 cm

Height of Container Z
= 65 - 13 - 4
= 48 cm

Volume of remaining water in Container Z
= 48 x 48 x 37
= 85248 cm³ 

Volume of remaining water in Container A
= 65 x 65 x 37
= 156325 cm³ 

Total volume of remaining water in the container
= 85248 + 156325
= 241573 cm³

1 ℓ = 1000 cm³
241573 cm³ = 241.573 ℓ

Answer(s): (a) 127.275 ℓ; (b) 241.573 ℓ