The figure, not drawn to scale, is made of two connected cubical containers, B and C. Container B is sealed at the top and completely filled to the brim. Container C is ²₃ filled with 125670 mℓ of water. The height of the water level in Container C is 4 cm higher than that in Container B. Height of Container C is 63 cm. Water is then drained from the container and the height of the water level from the base falls to 23 cm.

1. What is the capacity of Container C in litres?
2. What is the volume of water in the container now in litres?

(a)
²₃ of Container C = 125670 mℓ
¹₃ of Container C = 125670 ÷ 2 = 62835 mℓ
³₃ of Container C = 62835 x 3 = 188505 mℓ

1 ℓ = 1000 mℓ

Capacity of Container C = 188505 mℓ = 188.505 ℓ

(b)
Fraction of Container C not filled
= 1 - ²₃
= ¹₃

Height of Container C not filled
= ¹₃ x 63 cm
= 21 cm

Height of Container B
= 63 - 21 - 4
= 38 cm

Volume of remaining water in Container B
= 38 x 38 x 23
= 33212 cm³ 

Volume of remaining water in Container C
= 63 x 63 x 23
= 91287 cm³ 

Total volume of remaining water in the container
= 33212 + 91287
= 124499 cm³

1 ℓ = 1000 cm³
124499 cm³ = 124.499 ℓ

Answer(s): (a) 188.505 ℓ; (b) 124.499 ℓ