The figure, not drawn to scale, is made of two connected cubical containers, F and G. Container F is sealed at the top and completely filled to the brim. Container G is
23 filled with 113186 mℓ of water. The height of the water level in Container G is 4 cm higher than that in Container F. Height of Container G is 69 cm. Water is then drained from the container and the height of the water level from the base falls to 39 cm.
- What is the capacity of Container G in litres?
- What is the volume of water in the container now in litres?
(a)
23 of Container G = 113186 mℓ
13 of Container G = 113186 ÷ 2 = 56593 mℓ
33 of Container G = 56593 x 3 = 169779 mℓ
1 ℓ = 1000 mℓ
Capacity of Container G = 169779 mℓ = 169.779 ℓ
(b)
Fraction of Container G not filled
= 1 -
23 =
13 Height of Container G not filled
=
13 x 69 cm
= 23 cm
Height of Container F
= 69 - 23 - 4
= 42 cm
Volume of remaining water in Container F
= 42 x 42 x 39
= 68796 cm
3 Volume of remaining water in Container G
= 69 x 69 x 39
= 185679 cm
3 Total volume of remaining water in the container
= 68796 + 185679
= 254475 cm
3
1 ℓ = 1000 cm
3 254475 cm
3 = 254.475 ℓ
Answer(s): (a) 169.779 ℓ; (b) 254.475 ℓ