The figure is not drawn to scale. Tank U and Tank V have base areas of 3500 cm² and 2500 cm² respectively. Water was poured into an empty rectangular Tank U until it reached a height of 48 cm. Some of the water was then poured from Tank U into Tank V which contained 1.2 ℓ of water until the height of the water in both tanks were the same.

1. Find the new height of the water in Tank U.
2. How many litres of water were poured into Tank V?

(a)
Volume of water in Tank U
= 3500 x 48
= 168000 cm³ (Base area x height)

1 ℓ = 1000 cm³ 
1.2 ℓ = 1200 cm³ 

Total volume of Tank U and Tank V 
= 168000 + 1200
= 169200 cm³ 

Total base area of Tank U and Tank V 
= 3500 + 2500
= 6000 cm²

Height of Tank U after
= 169200 ÷ 6000
= 28.2 cm

(b)
Volume of water in Tank V after pouring
= 2500 x 28.2
= 70500 cm³ 

Volume of water poured into Tank V
= 70500 - 2500
= 68000 cm³ 

68000 mℓ = 68 ℓ

Answer(s): (a) 28.2 cm; (b) 68 ℓ