In the figure, not drawn to scale, O is the centre of the semi circle and OEFG is a rhombus. ∠OGH = 34°. Find
- ∠i
- ∠j.
(a)
OG = OH = Radius
∠GOH
= 180° - 34° - 34°
= 112° (Isosceles triangle)
∠i = ∠GOH = 112° (Corresponding angles, EF//OG)
(b)
∠j
= 180° - 112°
= 68° (Interior angles, FG//EO)
Answer(s): (a) 112°; (b) 68°