In the figure, not drawn to scale, O is the centre of the semi circle and OHJK is a rhombus. ∠OKL = 29°. Find
- ∠q
- ∠r.
(a)
OK = OL = Radius
∠KOL
= 180° - 29° - 29°
= 122° (Isosceles triangle)
∠q = ∠KOL = 122° (Corresponding angles, HJ//OK)
(b)
∠r
= 180° - 122°
= 58° (Interior angles, JK//HO)
Answer(s): (a) 122°; (b) 58°