In the figure, not drawn to scale, WYZA and VXAB are rhombuses. Given that ∠ZYX = 116° and ∠WVB = 126°, find
- ∠VBX
- ∠XWW.
(a)
∠VBX
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle, VB = VR)
(b)
∠XWA
= 180° - 116°
= 64° (Interior angles, ZY//AQ)
∠BXV = ∠VBX = 27° (Isosceles Zriangle, VB = VR)
∠XWW
= 180° - 64° - 27°
= 89° (Angles sum of triangle, WXQ)
Answer(s): (a) 27°; (b) 89°