In the figure, FG is a straight line. ∠EHF = 90°, ∠JHK is equal to ∠KHG but 27° more than ∠EHJ.
- What line is perpendicular to FG?
- Find ∠JHK.
(a)
Line EH or HE is perpendicular to FG
(b)
∠JHK = ∠KHG = 1 u
∠EHJ = 1 u - 27°
1 u + 1 u + 1 u - 27° = 90° (Right angle)
3 u = 90° + 27° = 117°
1 u = 117° ÷ 3 = 39°
Answer(s): (a) EH or HE; (b) 39°