The figure is made up of two squares and a triangle. The ratio of the area of Triangle M to that of Square P is 7 : 1. The ratio of the shaded area to that of the unshaded area is 1 : 5. If the difference between areas of Triangle M and Square N is 609 cm
2, what is the area of Square P?
Area of
Triangle M |
Area of
Square P |
Shaded
area |
Unshaded
area |
Total
area |
| 7x6 |
1x6 |
|
|
7x6 |
| |
|
1x7 |
5x7 |
6x7 |
| 42 u |
6 u |
7 u |
35 u |
42 u |
Area of Triangle M = Total area of the figure
Total area is the unchanged total. Make the total area the same.
LCM of 7 and 6 = 42
Area of Square N
= 7 u + 6 u
= 13 u
Difference between the areas of Triangle M and Square N
= 42 u - 13 u
= 29 u
29 u = 609
1 u = 609 ÷ 29 = 21
Area of Square P
= 6 u
= 6 x 21
= 126 cm
2 Answer(s): 126 cm
2 
