At 7 a.m., Owen left Hotel T in his car and travelled towards Hotel U at 92 km/h. At the same time, Seth left Hotel T in his car and travelled in the opposite direction towards Hotel V. When Seth reached Hotel V at 9.30 a.m., Owen was 10 km away from Hotel U.
- What was the distance from Hotel T to Hotel U?
- If the distance between Hotel U and Hotel V was 390 km, what was Seth's speed?
(a)
From 7 a.m. to 9.30. am = 2 h 30 min
60 min = 1 h
1 min =
160 h
30 min =
3060 =
12 h
2 h 30 min = 2
12 h
Distance from Hotel T to Hotel U
= 92 x 2
12 + 10
= 92 x
52 + 10
= 230 + 10
= 240 km
(b)
Distance travelled by Seth
= 390 - 240
= 150 km
Seth's speed
= 150 ÷ 2
12 = 150 ÷
52 = 150 x
25 = 60 km/h
Answer(s): (a) 240 km; (b) 60 km/h