At 7 a.m., Will left Hotel A in his car and travelled towards Hotel B at 90 km/h. At the same time, Zeph left Hotel A in his car and travelled in the opposite direction towards Hotel C. When Zeph reached Hotel C at 9.10 a.m., Will was 16 km away from Hotel B.
- What was the distance from Hotel A to Hotel B?
- If the distance between Hotel B and Hotel C was 380 km, what was Zeph's speed?
(a)
From 7 a.m. to 9.10. am = 2 h 10 min
60 min = 1 h
1 min =
160 h
10 min =
1060 =
16 h
2 h 10 min = 2
16 h
Distance from Hotel A to Hotel B
= 90 x 2
16 + 16
= 90 x
136 + 16
= 195 + 16
= 211 km
(b)
Distance travelled by Zeph
= 380 - 211
= 169 km
Zeph's speed
= 169 ÷ 2
16 = 169 ÷
136 = 169 x
613 = 78 km/h
Answer(s): (a) 211 km; (b) 78 km/h