Eva and Asher started off from the same place and drove at uniform speeds in the same direction round a 30 km circular racing track. Eva completed each round in 50 minutes. Asher took 100 minutes to complete each round.
- How far would Asher be behind Eva after 1 hour?
- How long after they started would it take Eva to meet Asher for the first time? Express your answer as a whole or mixed number in h.
(a)
60 min = 1 h
1 min =
160 h
50 min =
5060 h =
56 h
100 min =
10060 h = 1
23 h
Eva's speed
= 30 ÷
56= 30 x
65= 36 km/h
Asher's speed
= 30 ÷ 1
23= 30 x
35= 18 km/h
Distance between Eva and Asher after 1 hour
= 36 - 18
= 18 km
(b)
LCM of 50 and 100 = 100
100 min =
10060 h = 1
23 h
Time needed for Eva to meet Asher for the first time = 1
23 h
Answer(s): (a) 18 km; (b) 1
23 h