At 14 20, Daniel left Town P for Town Q, driving at a speed of 90 km/h. At 16 20, Ken also left Town P for Town Q driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 20, both of them passed a cafe that was 270 km away from Town Q. How many minutes earlier did Ken reach Town Q than Daniel?
Duration that Daniel travelled from 14 20 to 19 20 = 5 h
Distance that Daniel travelled
= 5 x 90
= 450 km
Distance between Town P and Town Q
= 450 + 270
= 720 km
Since Ken passed the cafe at the same time as Daniel, it means that Ken travelled 450 km in 3 hours.
Ken's speed during the journey
= 450 ÷ 3
= 150 km/h
Duration that Ken took to reach Town Q after passing the cafe
= 270 ÷ 150
= 1.8 h
Duration that Daniel took to reach Town Q after passing the cafe
= 270 ÷ 90
= 3 h
Difference between the time they took to reach Town Q
= 3 - 1.8
= 1.2 h
1 h = 60 min
1.2 h = 1.2 x 60 = 72 min
Ken reached Town Q 72 minutes earlier than Daniel.
Answer(s): 72 min