City F and City G is 444 km apart. Justin left City F for City G at 11.00 a.m. travelling at an average speed of 74 km/h. Elijah left City F later than Justin and caught up with him at 3.00 p.m. Elijah was travelling at a speed of 111 km/h.

1. At what time did Elijah leave City F?
2. How much later did Justin arrive in City G than Elijah? Express your answer in h as a fraction or mixed number.

(a)
From 11.00 a.m. to 3.00 p.m. = 4 h

Distance that Justin covered when Elijah caught up with Justin
= 4 x 74
= 296 km

Time that Elijah took to travel 296 km
= 296 ÷ 111
= 2²₃ h

1 h = 60 min
²₃ h = ²₃ x 60 = 40 min
2²₃ h = 2 h 40 min

Time that Elijah left City F:
2 h 40 min before 3.00 p.m. = 12.20 p.m.

(b)
Remaining distance that they had to cover to reach City G
= 444 - 296
= 148 km

Duration that Elijah had to travel before reaching City G
= 148 ÷ 111
= 1¹₃ h

Duration that Justin had to travel before reaching City G
= 148 ÷ 74
= 2 h

Duration that Justin took to arrive later than Elijah in City G
= 2 - 1¹₃
= ²₃ h

Answer(s): (a) 12.20 p.m.; (b) ²₃ h