At 9 a.m., Ken started from City W and travelled towards City X and his speed remained constant throughout. At 10 a.m., Jen started her journey from City W towards City X at an average speed of 90 km/h. Jen overtook Ken at 2 p.m. After overtaking, Jen carried on her journey at the same average speed and reached at City X at 2:30 p.m.
- Find Ken's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Jen had travelled until Jen overtook Ken
= 4 x 90
= 360 km
From 9 a.m. to 2 p.m. = 5 h
Ken's average speed
= 360 ÷ 5
= 72 km/h
(b)
From 10 a.m. to 2:30 p.m. = 4 h 30 min
1 h = 60 min
4 h 30 min = 4
30 60
h = 4
12 h
Distance between the two cities
= 4
12 x 90
=
92 x 90
= 405 km
Answer(s): (a) 72 km/h; (b) 405 km