City W and City X are 595 km apart. At 5.34 p.m., Ryan is travelling at a uniform speed left City W for City X while Caden set off from City X to City W along the same road at a uniform speed, which was 9 km/h slower than that of Ryan. The two met at 10.34 p.m.

1. Find the speed of Ryan.
2. If Caden continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Ryan and Caden to travel from 5.34 p.m. to 10.34 p.m. = 5 h

Average speed of Ryan and Caden
= 595 ÷ 5
= 119 km/h

Ryan's speed
= (119 + 9) ÷ 2
= 128 ÷ 2 
= 64 km/h

(b)
Caden's speed
= 64 - 9
= 55 km/h

Distance that Caden travelled in 5 h
= 5 x 55
= 275 km

Remaining distance that Caden needed to travel
= 595 - 275
= 320 km

Time that Caden needed to reach his destination after the two met
= 320 ÷ 55
= 5⁴⁵₅₅
= 5⁹₁₁ h

Answer(s): (a) 64 km/h; (b) 5⁹₁₁ h