City Y and City Z are 561 km apart. At 1.15 p.m., Glen is travelling at a uniform speed left City Y for City Z while Lee set off from City Z to City Y along the same road at a uniform speed, which was 11 km/h slower than that of Glen. The two met at 4.15 p.m.

1. Find the speed of Glen.
2. If Lee continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Glen and Lee to travel from 1.15 p.m. to 4.15 p.m. = 3 h

Average speed of Glen and Lee
= 561 ÷ 3
= 187 km/h

Glen's speed
= (187 + 11) ÷ 2
= 198 ÷ 2 
= 99 km/h

(b)
Lee's speed
= 99 - 11
= 88 km/h

Distance that Lee travelled in 3 h
= 3 x 88
= 264 km

Remaining distance that Lee needed to travel
= 561 - 264
= 297 km

Time that Lee needed to reach his destination after the two met
= 297 ÷ 88
= 3³³₈₈
= 3³₈ h

Answer(s): (a) 99 km/h; (b) 3³₈ h