At 09 15, Hilda left Town W and cycled towards Town X. Fanny left Town W and cycled towards Town X at 09 45. Fanny's cycling speed was 2 km/h faster than Hilda. At 13 15, Fanny caught up with Hilda. Find the cycling speed of each cyclist.
- Hilda
- Fanny
(a)
Duration that Fanny cycled from 09 45 to 13 15
= 3
3060 = 3
12 h
Distance that Fanny cycled more than Hilda
= 3
12 x 2
= 7 km
However, since Hilda left 30 minutes earlier than Fanny and Fanny caught up with Hilda, it means that Hilda has cycled 7 km in 30 min.
1 h = 60 min
30 min = 30 ÷ 60 =
12 h
Hilda's cycling speed
= 7 ÷
12 = 7 x
21 = 14 km/h
(b)
Fanny's cycling speed
= 14 + 2
= 16 km/h
Answer(s): (a) 14 km/h ; (b) 16 km/h
