Asher started driving from City T towards City U at 14 40 at an average speed of 60 km/h. Mark began driving from City T towards City U at 16 30 at an average speed of 110 km/h.

1. At what time did Mark pass Asher on the road?
2. 1¹₁₀ hours after passing Asher, Mark reached City U. At what time did Asher reach City U?

(a)
From 14 40 to 16 30 = 1 h 50 min

Time that Asher travelled before Mark started driving = 1 h 50 min

1 h = 60 min
1 h 50 min = 1⁵⁰₆₀ h = 1⁵₆ h

Distance that Asher travelled before Mark started driving
= 1⁵₆ x 60
= ¹¹₆ x 60
= 110 km

Difference between Mark's and Asher's speed
= 110 - 60
= 50 km/h

Time that Mark took to catch up with Asher
= 110 ÷ 50
= 2.2 h
= 2 h 12 min

2 h 12 min after 16 30 = 18 42

Time that Mark passed Asher on the road = 18 42

(b)
1¹₁₀ h = 1 h 6 min

Total time that Mark travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min

3 h 18 min = 3¹⁸₆₀h = 3³₁₀h

Distance between City T and City U
= 3³₁₀ x 110
= 363 km

Time that Asher travelled from City T to City U
= 363 ÷ 60
= 6.05 h
= 6 h 3 min

6 h 3 min after 14 40 = 20 43

Time that Asher reached City U = 20 43

Answer: (a) 18 42; (b) 20 43