Sean started driving from City Y towards City Z at 14 40 at an average speed of 60 km/h. Jenson began driving from City Y towards City Z at 16 30 at an average speed of 110 km/h.
- At what time did Jenson pass Sean on the road?
- 1110 hours after passing Sean, Jenson reached City Z. At what time did Sean reach City Z?
(a)
From 14 40 to 16 30 = 1 h 50 min
Time that Sean travelled before Jenson started driving = 1 h 50 min
1 h = 60 min
1 h 50 min = 1
5060 h = 1
56 h
Distance that Sean travelled before Jenson started driving
= 1
56 x 60
=
116 x 60
= 110 km
Difference between Jenson's and Sean's speed
= 110 - 60
= 50 km/h
Time that Jenson took to catch up with Sean
= 110 ÷ 50
= 2.2 h
= 2 h 12 min
2 h 12 min after 16 30 = 18 42
Time that Jenson passed Sean on the road = 18 42
(b)
1
110 h = 1 h 6 min
Total time that Jenson travelled
= 1 h 6 min + 2 h 12 min
= 3 h 18 min
3 h 18 min = 3
1860h = 3
310h
Distance between City Y and City Z
= 3
310 x 110
= 363 km
Time that Sean travelled from City Y to City Z
= 363 ÷ 60
= 6.05 h
= 6 h 3 min
6 h 3 min after 14 40 = 20 43
Time that Sean reached City Z = 20 43
Answer: (a) 18 42; (b) 20 43