Luke left City B for City A at 07 49. Esther left City B for City C at the same time. At 11 49, they were 780 km apart. Both maintained a constant speed and reached their destination at the same time at 13 33.
- Find the distance between Cities A and C.
- If Esther was 67 the speed of Luke, find Luke's speed.
(a)
Time taken for Luke and Esther to travel 07 49 to 11 49 = 4 h
Time taken for Luke and Esther to travel 07 49 to 13 33 = 5 h 44 min = 5
4460 h = 5
1115 h
Distance travelled by Luke and Esther in 1 hour
= 780 ÷ 4
= 195 km
Total distance
= 5
1115 x 195
= 1118 km
(b)
Esther's distance : Luke's distance
6 : 7
Esther's speed : Luke's speed
6 : 7
13 u = 195 km
1 u = 195 ÷ 13 = 15 km
Luke's speed
= 7 u
= 7 x 15
= 105 km/h
Answer(s): (a) 1118 km; (b) 105km/h