PSLE
Three men, Ace, Lee and Sam had the same number of notes. Lee and Ace each had of mix of $50-notes and $10-notes. Lee had 16 $10-notes while Ace had 21 $10-notes. Sam had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Lee and Ace's notes? 
3. Ace used all his $50-notes to buy a gift. Sam then had $1190 more than Ace. How many $50-notes did Sam have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Ace had more $10-notes than Lee while Sam had only the $50-notes.  

Since Ace had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 21 - 16
= 5

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Lee's and Ace's notes
= 5 x 40
= $200

(c)
Value of $10-notes that Ace had left
= 21 x 10
= $210

Total value that Sam had
= 1190 + 210
= $1400

Number of $50-notes that Sam had
= 1400 ÷ 50
= 28

Answer(s): (a) Ace; (b) $200; (c) 28