There were some oranges and chikoos in Container L and Container M. In Container L, the ratio of the oranges to the number of chikoos was 2 : 1. In Container M, the ratio of the number of oranges to the number of chikoos was 3 : 1. There were 3 times as many fruits in Container L as in Container M. After another 72 chikoos were put into Container M, the ratio of the number of oranges to the number of chikoos in Container M became 1 : 3. How many fruits were there in Container M in the end?

Container L		Container M
3x4 = 12 u		1x4 = 4 u
Oranges	Chikoos	Oranges	Chikoos
2x4	1x4	3	1
8 u	4 u	3 u	1 u

The total number of fruits in Container L is repeated.  Make the total number of fruits in Container L the same.  LCM of 3 and 3 is 12.

The total number of fruits in Container M at first is repeated.  Make the total number of fruits in Container M the same.  LCM of 1 and 4 is 4.

	Container L		Container M
	Oranges	Chikoos	Oranges	Chikoos
Before	8 u	4 u	3 u	1 u
Change				+ 72
After	8 u	4 u	1x3 = 3 u	3x3 = 9 u

Number of oranges in Container M remains unchanged.  Make the number of oranges in Container M the same.  LCM of 3 and 1 is 3.

Number of chikoos put into Container M
= 9 u - 1 u
= 8 u

8 u = 72

1 u = 72 ÷ 8 = 9

Number of fruits in Container M in the end
= 3 u + 9 u
= 12 u
= 12 x 9
= 108

Answer(s): 108