Betty, Yoko and Opal were playing with beads. Betty started with 88 beads and in the first game, she won ¹₂ more beads from Yoko. In the second game, Betty lost ³₈ of her original number of beads to Opal. Yoko lost as many beads as Betty to Opal. In the final game, Betty won ¹₄ of her original number of beads from Yoko. All of them ended up with the same number of beads.

1. How many beads did Betty have in the end?
2. How many beads did Yoko have at first?

	Betty	Yoko	Opal
Before	88
First game	+ 44	- 44
Second game	- 33		+ 33
		- 33	+ 33
Final game	+ 22	- 22
After	1 u	1 u	1 u

(a)
Number of beads that Betty won from Yoko
= ¹₂ x 88
= 44

Number of beads that Betty lost to Opal
= ³₈ x 88
= 33

Number of beads that Betty won from Yoko
= ¹₄ x 88
= 22

Number of beads that Betty had in the end
= 88 + 44 - 33 + 22
= 121

(b)
Number of beads that Yoko had at first
= 1 u + 22 + 33 + 44
= 121 + 22 + 33 + 44
= 220 

Answer(s): (a) 121 ; (b) 220