Container G and Container H were filled completely with bread flour. The total mass of ¹₃ of the bread flour in Container H and ¹₁₁ of the bread flour in Container G was 510 g. If ²₁₁ of the bread flour in Container G was poured out, the total mass of the bread flour in both containers became 2.43 kg. How much bread flour was in

1. Container G in grams?
2. Container H in grams?

(a)
Let the mass of the bread flour in Container H be H.
Let the mass of the bread flour in Container G be G.

¹₃ H + ¹₁₁ G = 510 --- (1)

Fraction of the bread flour left in Container G after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
2.43 kg = 2430 g

1 H + ⁹₁₁ G = 2430
1 H = 2430 - ⁹₁₁ G --- (2)

Make H the same.

(1)_x3
³₃ H + ³₁₁ G = 1530
1 H + ³₁₁ G = 1530
1 H = 1530 - ³₁₁ G --- (3)

(3) = (2) 
1530 - ³₁₁ G = 2430 - ⁹₁₁ X
⁹₁₁ G - ³₁₁ G = 2430 - 1530
⁶₁₁ G = 900
¹₁₁ G = 900 ÷ 6 = 150

¹¹₁₁ G = 11 x 150 = 1650

1 G = 1650

Mass of Container G = 1650 g

(b)
From (1)
¹₃ H + 150 = 510
¹₃ H = 510 - 150 = 360

³₃ H = 3 x 360 = 1080

1 H = 1080

Mass of Container H = 1080 g

Answer(s): (a) 1650 g; (b) 1080 g