Container N and Container P were filled completely with curry powder. The total mass of ¹₆ of the curry powder in Container P and ¹₁₃ of the curry powder in Container N was 500 g. If ²₁₃ of the curry powder in Container N was poured out, the total mass of the curry powder in both containers became 3.75 kg. How much curry powder was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the curry powder in Container P be P.
Let the mass of the curry powder in Container N be N.

¹₆ P + ¹₁₃ N = 500 --- (1)

Fraction of the curry powder left in Container N after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
3.75 kg = 3750 g

1 P + ¹¹₁₃ N = 3750
1 P = 3750 - ¹¹₁₃ N --- (2)

Make P the same.

(1)_x6
⁶₆ P + ⁶₁₃ N = 3000
1 P + ⁶₁₃ N = 3000
1 P = 3000 - ⁶₁₃ N --- (3)

(3) = (2) 
3000 - ⁶₁₃ N = 3750 - ¹¹₁₃ X
¹¹₁₃ N - ⁶₁₃ N = 3750 - 3000
⁵₁₃ N = 750
¹₁₃ N = 750 ÷ 5 = 150

¹³₁₃ N = 13 x 150 = 1950

1 N = 1950

Mass of Container N = 1950 g

(b)
From (1)
¹₆ P + 150 = 500
¹₆ P = 500 - 150 = 350

⁶₆ P = 6 x 350 = 2100

1 P = 2100

Mass of Container P = 2100 g

Answer(s): (a) 1950 g; (b) 2100 g