The safari park tickets are priced at $20 and $16. The number of $20-dollar tickets available is 2
45 that of the number of $16-dollar tickets. 3 out of 5 of the $20-dollar tickets and all the $16-dollar tickets were sold. The ticket sales amounted to $8680. How much more would have been collected if all the tickets were sold?
|
$20 |
$16 |
Comparing $20 and $16 tickets at first |
14x5 = 70 u |
5x5 = 25 u |
Before |
5x14 = 70 u |
|
Change |
- 3x14 = - 42 u |
- 25 u |
After |
2x14 = 28 u |
0 u |
The number of 20 tickets at first is repeated. Make the number of 20 tickets the same. LCM of 5 and 14 is 70.
2
45 =
145 Number of $20 tickets : $16 tickets = 14 : 5
|
$20 |
$16 |
Total |
Number |
42 u |
25 u |
|
Value |
$20 |
$16 |
|
Total value |
840 u |
400 u |
$8680 |
Total amount collected from the sale of the sold tickets
= 840 u + 400 u
= 1240 u
1 u = 8680 ÷ 1240 = 7
Number of $20-tickets left unsold
= 28 u
= 28 x 7
= 196
More amount to be collected if all the tickets were sold
= 196 x 20
= $3920
Answer(s): $3920