Fiona and Winnie have some croissants each. If Fiona gives Winnie 16 croissants, Fiona will have
12 as many croissants as Winnie. If Fiona gives Winnie 5 croissants, they will have an equal number of croissants. How many croissants does Winnie have at first?
|
Case 1 |
Case 2 |
|
Fiona |
Winnie |
Fiona |
Winnie |
Before |
1 u + 16 |
2 u - 16 |
1.5 u + 5 |
1.5 u - 5 |
Change |
- 16 |
+ 16 |
- 5 |
+ 5 |
After |
1 u |
2 u |
1.5 u |
1.5 u |
Total number of croissants that Fiona and Winnie have
= 1 u + 2 u
= 3 u
Number of croissants that Fiona and Winnie each has in the end is the same.
Number of croissants that Fiona and Winnie each has in the end in Case 2
= 3 u ÷ 2
= 1.5 u
Number of croissants that Fiona had at first is the same in Case 1 and Case 2.
1.5 u + 5 = 1 u + 16
1.5 u - 1 u = 16 - 5
0.5 u = 11
1 u = 11 ÷ 0.5 = 22
Number of croissants that Winnie has
= 2 u - 16
= 2 x 22 - 16
= 44 - 16
= 28
Answer(s): 28