Irene had 168 pencils.
37 were blue and the rest were grey and brown. The ratio of the number of grey pencils to the number of brown pencils was 1 : 2. Irene decided to buy some more blue pencils to increase the number of blue pencils to half of the total number of pencils.
- How many less grey pencils than blue pencils did he have at first?
- How many more blue pencils did he have to buy?
Blue pencils |
Grey pencils |
Brown pencils |
Total |
3x3 |
4x3 |
|
|
1x4 |
2x4 |
|
9 u |
4 u |
8 u |
168 |
|
Blue pencils |
Grey pencils |
Brown pencils |
Before |
9 u |
4 u |
8 u |
Change |
+ ? |
|
|
After |
12 u |
12 u |
Comparing blue, grey and brown pencils in the end |
1 |
1 |
(a)
The total number of grey pencils and brown pencils is repeated. Make the total number of grey pencils and brown pencils the same. LCM of 4 and 3 is 12.
Total number of pencils at first
= 9 u + 4 u + 8 u
= 21 u
21 u = 168
1 u = 168 ÷ 21 = 8
Number of less grey pencils than blue pencils at first
= 9 u - 4 u
= 5 u
= 5 x 8
= 40
(b)
Number of more blue pencils that Irene had to buy
= 12 u - 9 u
= 3 u
= 3 x 8
= 24
Answer(s): (a) 40; (b) 24