A container contains some kiwis, mangosteens and pears. 0.2 of the kiwis is equal to 70% of the mangosteens. The number of pears is ⁴₅ of the total number of mangosteens and kiwis. If there are 260 less mangosteens than pears, how many fruits are there in the container altogether?

Kiwis	Mangosteens	Pears
7x5	2x5
5x9		4x9
35 u	10 u	36 u

0.2 = ²₁₀= ¹₅
70% = ⁷⁰₁₀₀ = ⁷₁₀

0.2 of the kiwis is equal to 70% of the mangosteens. Make the numerators the same.  LCM of 1 and 7 is 7.

1x75x7 of the kiwis = 7x110x1 of the mangosteens
735 of the kiwis = 710 of the mangosteens 

Kiwis : Mangosteens
35 : 10 _(÷5)
7 : 2

The total number of kiwis and mangosteens is repeated.  Make the total number of kiwis and mangosteens the same.  LCM of 9 and 5 is 45.

Number of less mangosteens than pears
= 36 u - 10 u
= 26 u

26 u = 260

1 u = 260 ÷ 26 = 10

Number of the fruits in the container altogether
= 35 u + 10 u + 36 u
= 81 u
= 81 x 10
= 810

Answer(s): 810