A container contains some oranges, chikoos and starfruits. 0.6 of the oranges is equal to 80% of the chikoos. The number of starfruits is ³₄ of the total number of chikoos and oranges. If there are 90 more starfruits than chikoos, how many fruits are there in the container altogether?

Oranges	Chikoos	Starfruits
4x4	3x4
4x7		3x7
16 u	12 u	21 u

0.6 = ⁶₁₀= ³₅
80% = ⁸⁰₁₀₀ = ⁴₅

0.6 of the oranges is equal to 80% of the chikoos. Make the numerators the same.  LCM of 3 and 4 is 12.

3x45x4 of the oranges = 4x35x3 of the chikoos
1220 of the oranges = 1215 of the chikoos 

Oranges : Chikoos
20 : 15 _(÷5)
4 : 3

The total number of oranges and chikoos is repeated.  Make the total number of oranges and chikoos the same.  LCM of 7 and 4 is 28.

Number of more starfruits than chikoos
= 21 u - 12 u
= 9 u

9 u = 90

1 u = 90 ÷ 9 = 10

Number of the fruits in the container altogether
= 16 u + 12 u + 21 u
= 49 u
= 49 x 10
= 490

Answer(s): 490